gjej x ne ekuacion kuadratic x = solve('a*x^2 + b*x + c = 0'); %gjej x ne nje ekuacion te tille x = solve('p*sin(x) = r'); %gjej x ose y ne ekuacion me 2 variabla [x,y] = solve('x^2 + x*y + y = 3','x^2 - 4*x + 3 = 0'); %ose gjej te panjohurat a,u,v ne te tille ekuacion [a,u,v] = solve('a*u^2 + v^2','u - v = 1','a^2 - 5*a + 6'); %ose keshtu! [x,y] = solve('sin(x+y)-exp(x)*y = 0','x^2-y = 2') % derivati i x^3 sa eshte? diff(x^3); %integrali i x^3? Mos harro boundary!!!!!!!!!!!  int(x^3); %me ekuacionet diferenciale; y = dsolve('Dy = -a*y') %%%'D %% konditat e para(si thuhet ne shqip initial conditions?)  y = dsolve('Dy = -a*y','y(0) = 1');  %with second derivative y = dsolve('D2y = -a^2*y', 'y(0) = 1, Dy(pi/a) = 0') % A nonlinear equation produces two solutions in a vector. y = dsolve('(Dy)^2 + y^2 = 1','y(0) = 0') %ose generate a possibly familiar test matrix, the 5-by-5 Hilbert matrix. H = sym(hilb(5)) H = [ 1, 1/2, 1/3, 1/4, 1/5] [ 1/2, 1/3, 1/4, 1/5, 1/6] [ 1/3, 1/4, 1/5, 1/6, 1/7] [ 1/4, 1/5, 1/6, 1/7, 1/8] [ 1/5, 1/6, 1/7, 1/8, 1/9] % The determinant d = det(H); % Find the characteristic polynomial. p = poly(H); % Try to factor the characteristic polynomial just found. factor(p); % Compute 50 digit numerical approximations to the eigenvalues. digits(50); e = eig(vpa(H));